$$\begin{pmatrix} -2i&-3&7\\ 0&-1-2i&5\\ 0&-1&1-2i \end{pmatrix} \mathbf{v} =0 \implies \begin{pmatrix} -2i&-3&7\\ 0&-1-2i&5\\ 0&0&0 \end{pmatrix} \mathbf{v} =0.$$
How do I get the second matrix? What're the steps?
How to do this matrix to RREF form?
$\endgroup$ 11 Answer
$\begingroup$Multiply row 3 by $1+2i$. Then rows 2 and 3 will be the same and you can subtract row 2 from 3.
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