Reverse column output with sort command

I have to sort all of the words from a file given as parameter in a shell script. Here is the one-liner:

tr [:space:] '\n' <$1 | sort -nrk2,2 | uniq -c |sed 's/^ \+//g'

Basically, if I have something like this in my file:

bla bla bla bla hu hu hu

It will output

4 bla
3 hu

I want them to be something like

bla 4
hu 3

2 Answers

You could replace your sed command with a simple awk command that swaps the field order

... | awk '{print $2,$1}'

There are many, many ways of doing this. Steeldriver already gave you the classic awk approach. Here are some other choices:

Use sed to capture two groups of non-whitespace (\S) characters and then switch them around:
```
... | sed -E 's/\s*(\S+)\s+(\S+)/\2 \1/'
```
Use perl. Its -a switch makes it work like awk. It will automatically split each input line on whitespace and save each field as an element of the array @F. Therefore, the 1st field will be $F[0], the second $F[1] etc.:
```
... | perl -lane 'print "$F[1] $F[0]"'
```
Use Perl for the whole thing:
```
perl -lane '$k{$_}++ for @F; }{ print "$_ $k{$_}" for keys(%k)' "$1"
```
Here, perl reads the input file line by line and applies the script to each line. $k{$_}++ for @F saves each word (each field from @F) as a key in the hash %k and increments the associated value by one each time the word is seen. Then, after the file has been processed (that's what the }{ means), it will print the word ($_) and the number of times it was seen ($k{$_}) for each key stored in the hash.
Use awk for the whole thing:
```
awk '{for(i=1;i<=NF;i++){a[$i]++}}END{for(i in a){print i,a[i]}}' "$1"
```
The first for loop iretares over each field and adds one to the value associated with that field in the array a. Then, at the end of the file, it loops over each element in a and prints the element (the word) and the associated value (the number of times the word was seen).

Use the shell with your original pipeline:

... | while read a b; do echo "$b $a"; done