I can't find a way to simplify this boolean algebra

xyz' + x'y + x'z

the answer from boolean expression calculator on the internet is

x'z + yz'

I know the end

x'z

same like the answer. but I can't find a way to simplify

xyz' + x'y = yz'

1 Answer

We can only derive$$xyz'+x'y=y(xz'+x')=y(xz'+x'(z+z'))=\\ =y((x+x')z'+x'z)=y(z'+x'z)=yz'+yx'z$$But it's enough to get$$xyz'+x'y+x'z=yz'+yx'z+x'z=yz'+(1+y)x'z=yz'+x'z$$