Find the area common to the inside of the cardioid $r = 1+\sin \theta$ and the outside of the cardioid $r = 1 + \cos \theta$.

$\begingroup$

Function Plotter graph:


enter image description here


I think the formula is

$$A = \frac 1 2 \int_{\alpha}^{\beta} (\text{outer})^2 - (\text{inner})^2 d\theta$$

where $\alpha, \beta$ are where they intersect in $[0, 2\pi]$.

This is what I got based on that

$$A = \frac 1 2 \int_{3\pi/4}^{5\pi/4} (1+\sin \theta)^2 - (1+\cos \theta)^2 d\theta$$

Is that right?

$\endgroup$ 2 Reset to default

Know someone who can answer? Share a link to this question via email, Twitter, or Facebook.

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password

Post as a guest

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

You Might Also Like