$ (e^{2x})=(e^x)^2$
Can Some one explain how these two are the same? I know it is trick, but I cannot see how it fits into the exponent rules.
$\endgroup$ 41 Answer
$\begingroup$Asuuming you're familiar with $e^x\cdot e^y=e^{x+y}$ then $e^x\cdot e^x=e^{x+x}=e^{2x}$.
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