I know that the product of two Gaussians is a Gaussian, and I know that the convolution of two Gaussians is also a Gaussian. I guess I was just wondering if there's a proof out there to show that the convolution of two Gaussians is a Gaussian.
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$\begingroup$- the Fourier transform (FT) of a Gaussian is also a Gaussian
- The convolution in frequency domain (FT domain) transforms into a simple product
- then taking the FT of 2 Gaussians individually, then making the product you get a (scaled) Gaussian and finally taking the inverse FT you get the Gaussian
Fourier Transform will help you out to conclude that the convolution is also a gaussian.
$\endgroup$ 3 $\begingroup$See this for two common alternatives.
$\endgroup$ 1 $\begingroup$I think this pdf file can help you.
$\endgroup$ 1 $\begingroup$There is a proof for product of multivariate Gaussian PDFs in here. Maybe this can help:
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