If we try to divide any two random arbitrarily long rational numbers like
103850.2387209375029375092730958297836958623986868349693868398659825528365...and
127.123123123...Is it guaranteed that the result is also a rational number?
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$\begingroup$The quotient of two rationals is always a rational.
For if $\alpha = \frac{a}{b}$ and $\beta = \frac{c}{d}$ with $a, b, c, d$ integers with none of $b, c, d$ being zero, then
$$\frac{\alpha}{\beta} = \frac{ad}{bc}$$
is a quotient of integers, and so is rational.
$\endgroup$ 1 $\begingroup$If we get an irrational number by dividing a rational number by another rational number, then product of rationals won't be a binary operation in $\mathbb{Q}$. But we know that $\mathbb{Q}\setminus \{0\}$ is a group with respect to multiplication.
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